At what temperature will 0.005 mol of gas occupy 600 mL at a pressure of 750 mm Hg? (R=0.0821 L atm / K mol)
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If I am not mistaken this question should solve using ideal gas law.
PV = nRT
Volume must be in liters and pressure must be in atm.
(0.987)(0.6) = (0.005)(0.0821)T
0.5922 = (0.0004105)T
T = 1442.63
The temperature will needed is 1442.63 K
I am not sure whether my answer is right. But you could take a look in it.
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