Question

At what temperature will a 0.05 molal solution of glucose exert an osmotic pressure of 1.642 atm?

Answer 1

Answer:

Temperature = 400.48 K

Explanation:

We know that,

π = cRT

where,

π is the osmotic pressure

c is the concentration

R is the universal gas costant

T is the temperature

Given that,

π = 1.642 atm

c = 0.05 m

R = 0.082 L atm mol⁻¹ K⁻¹

T = ?

Putting these values in we get,

1.642 = 0.05 * 0.082 * T

T = 400.48 K

T = 127.48 ° C