At what temperature will be the molar kinetic energy of 0.3 mole of
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Answer:
Explanation:
KE = 3nRT/2
(KE)He /(KE)Ar = (moles of He)(temp of He)/(moles of Ar)(temperature of Ar)
1 = (0.3)T/(0.4)(400)
T =>400*4/3
=>533K
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KE = 3nRT/2(KE)He /(KE)Ar = (moles of He)(temp of He)/(moles of Ar)(temprature of Ar)1 = (0.3)T/(0.4)(400) T = 400*4/3 =533K.
The moles are taking place by considering factors and thus valuate in addressing with right choice.
It is used to simplifying the factors and consider moles.
The molecular ranges have been evaluated.
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