Question

At what temperature will hydrogen molecules have the same KE as nitrogen molecules at 280K?

Answer 1

Answer:

At 280 K, hydrogen gas molecule will have same kinetic energy as that of the nitrogen gas molecule.

Explanation:

Kinetic Energy of gas molecule by the equation:

$K=\frac{3RT}{2N_A}$

where,

K = Average kinetic energy

R = Gas constant

T = Temperature of the system

$N_A$ = Avogadro's number

Kinetic Energy of nitrogen gas molecule at 280 K:

$K.E=\frac{3R\times 280 K}{2N_A}$ ..[1]

Kinetic Energy of hydrogen gas molecule at T':

$K.E'=\frac{3R\times T'}{2N_A}$ ..[2]

[1] = [2]

Kinetic Energy of nitrogen gas molecule :

$K.E=\frac{3R\times 280 K}{2N_A}=\frac{3R\times T'}{2N_A}$

T' = 280 K

Answer 2

Refer to the above attachment to see the solution.