Question

At what temperature will most probable speed of
the molecules of the second member of homolo-
gous series C H2-2 be the same as that of So,
at 527°C​

Answer 1

Answer:

At the speed of light this will help you

Answer 2

$We \: know \: that \: the \: formula \\ of \: most \: probable \: speed -$

$v = \sqrt{ \frac{8RT}{\pi \: M} }$

T= Temperature

M= Molecular mass

Second member of homologous series

$C_{n}H_2n-2$

$C_{2}H_2.2-2 = C_{2}H_2$

$Molecular mass of C_{2}H_2 = 26$

$Molecular\:mass \:of \: oxygen=32$

$Given, \: temperature \: T=527 \degree</p><p> C(for \: oxygen)$

$T_1(temperature \: of \: homologous\\series)=?$

$(\sqrt{\frac{8RT}{\pi\:M}}) o_2=(\sqrt{ \frac{8RT}{\pi\: M}})C_{n}H_2n-2$

T_1 = \frac{527\times 32}{26}=

648.61\degree[/tex]