Question

At what temperature will the mean molecular energy of a perfect gas be one-third of its value at 27°C?
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Answer 1

Answer:

100 K or (10)1

Explanation:

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Answer 2

Helo mate here your ans

Mean KE∝T

therefore at T=27 which in kelvin becomes 300 K

So KE will be 1/3 when temperature becomes 1/3 which is 300/3=100K

Hope this ans help you.. xd..