Chemistry, asked by prabhavpavan7685, 1 year ago

At what temperature will the oxygen molecules have the same root mean square speed as hydrogen molecules have at 100 kelvin

Answers

Answered by VemugantiRahul
8
Hi there!
Here's the answer:

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Given,
Temperature of Hydrogen Molecule (T_{0})= 100\: K

Molecular weight of hydrogen (M_{H})= 2
Molecular weight of 0xygen (M_{0}) = 32

We have,
RMS Velocity V_{m} = \sqrt{\frac{3RT}{M}}

RMS velocity of Hydrogen = \sqrt{\frac{3RT_{0}}{M_{H}}}

=\sqrt{\frac{3R×10}{2}}

RMS velocity of Oxygen V_{O__{2}} =

\sqrt{\frac{3RT_{0}}{M_{0}}}

=\sqrt{\frac{3RT_{0}}{32}}

Given that the RMS velocities are equal,
\implies V_{H__{2}} = V_{O__{2}}

\implies \sqrt{\frac{3R×10}{2}} = \sqrt{\frac{3RT_{0}}{32}}

\implies \frac{10}{2} = \frac{T_{0}}{32}

Cross Multiply

\implies 2T_{0} = 320

\implies T_{0} = 160


•°• Temperature of Oxygen = 160 K

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Answered by Anonymous
3

Answer:

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