Question

at what temperature will The RMS speed of air molecules be doubled at of STP​

Answer 1

Answer:

819⁰C

Explanation:

v(rms) = √(3RT / M)

At T = T₀, v(rms) = √(3RT / M)

But at temperature T, v(rms) = 2 × √(3RT₀ / M)

⇒ √(3RT / M) = 2 √(3RT₀ / M) ⇒ √T = √(4T₀) ⇒ T = 4T₀

T = 4 × 273 K = 1092 K

Therefore, T = 819°C