At what temperature will the rms speed of oxygen
molecules become just sufficient for escaping from
the Earth's atmosphere?
(Given :
Mass of oxygen molecule (m) = 2.76 x 10-26 kg
Boltzmann's constant kg = 1.38 x 10-23 JK-1)
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Answer:
Ves = Vrms
11.2 x 10^3 = √(3KT/m)
T = [(11.2 x 10^3)^2 m] / 3k
Putting value of m and k
T = 8.360 x 10^4 k
Explanation:
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