Physics, asked by chandu9510, 1 year ago

At what temperature will the rms speed of oxygen molecules become just sufficient for escaping from the Earth's atmosphere? (Given: Mass of oxygen molecule (m) 2.76x 10-26 kg Boltzmann's constant kp 138 x 10 23 J K1)

Answers

Answered by sachin526
203
Ves = Vrms

11.2 x 10^3 = √(3KT/m)

T = [(11.2 x 10^3)^2 m] / 3k

Putting value of m and k
T = 8.360 x 10^4 k
Answered by goldenstar09
80

Explanation:

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