at what temperature will the speed of sound be double its value at 273K
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Answered by
112
the speed of the sound in air is given by the following relation
v=√yRT/M
Here,
y=adiabatic index
R=gas constant
T=temperature
M=molar mass(kg/mol)
therefore;
the speed of sound at To(=273k) will be............(i)
the speed of sound at unknown temperature T will be
v^1=√yRT^1/M
Hence,we know that v^1=2vo at temperature t^1
so 2vo=√yRT^1/M.............(ii)
by equating (1)&(2) we get/while solving further we get
To=(1/4)T/T=4To=4×273K
Thus,the temperature at which the speed of sound would be double is
T=1092K or T=819°C
v=√yRT/M
Here,
y=adiabatic index
R=gas constant
T=temperature
M=molar mass(kg/mol)
therefore;
the speed of sound at To(=273k) will be............(i)
the speed of sound at unknown temperature T will be
v^1=√yRT^1/M
Hence,we know that v^1=2vo at temperature t^1
so 2vo=√yRT^1/M.............(ii)
by equating (1)&(2) we get/while solving further we get
To=(1/4)T/T=4To=4×273K
Thus,the temperature at which the speed of sound would be double is
T=1092K or T=819°C
Answered by
151
The temperature at which the speed of sound be double its value at 273K is 819 Celsius.
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