Question

at what temperature will the speed of sound in air become double of its value at zero degree celsius

Answer 1

solution

=>. v is proportional to root of it's tap in k

v= k√T

for doubling the speed v2/ v1 =2

=> v2/v1= √T2/√T1= 2

=> T2/ T1= 4

T1= 0+273= 273

so. T2= 4× 273= 1092 k

= 1092-273

= 819° C