at what temperature will the total ke of 0.3 mol of he be the same as the total ke of 0.40 mol of ar at 400 k
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Answered by
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KE = 3nRT/2(KE)He /(KE)Ar = (moles of He)(temp of He)/(moles of Ar)(temprature of Ar)1 = (0.3)T/(0.4)(400) T = 400*4/3 =533K.
The moles are taking place by considering factors and thus valuate in addressing with right choice.
It is used to simplifying the factors and consider moles. The molecular ranges have been evaluated
Answered by
8
Answer: KE OF helium =ke of argon
By solving we get 533.33
Explanation:
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