At what temperature will the total KE of 0.3 Mol of He be same as the total KE of 0.4 Mol of AR at 400 K?
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Answer:
533.33k
Explanation:
kE=3/2nRT
let temperature of he be T
kE of o.3 mole of he at To=kE of0.4mole of AR at 400k
3/2×0.3×R×T=3/2×0.4×R×400
T=533.33k
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