at what temperature will the total kinetic energy of 0.3 mol of he be the same as the total kinetic energy of 0.4mol of Ar at 400 kelvin
muskan371:
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Answers
Answered by
14
KE = 3nRT/2
(KE)He /(KE)Ar = (moles of He)(temp of He)/(moles of Ar)(temperature of Ar)
1 = (0.3)T/(0.4)(400)
T =>400*4/3
=>533K
(KE)He /(KE)Ar = (moles of He)(temp of He)/(moles of Ar)(temperature of Ar)
1 = (0.3)T/(0.4)(400)
T =>400*4/3
=>533K
Answered by
3
Answer: 533k
Explanation:
KE = 3nRT/2
(KE)He /(KE)Ar = (moles of He)(temp of He)/(moles of Ar)(temperature of Ar)
1 = (0.3)T/(0.4)(400)
T =>400*4/3
=>533K
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