At what temperature would 500 cc of gas measured at 20°C, occupy half of its original volume ? [Pressure
is kept constant]
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Answer:
I assume you know equation for ideal gas :
P1*V1/T1 = P2*V2/T2 (for same mass of gas)
Let
P1 = P; V1 = V; T1 = 20 deg C = 293 K (given)
P2 = 2P; V2 = 2V; T2 = ? (as per your question)
by substituting all these in ideal gas equation we get
P*V/293 = (2*P)*(2*V)/T2
T2 = 4 * 293 = 1172 K = 899 deg C
T2 = 899 deg C (final temperature of the gas)
Now try to figure out your equation!
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Hey, here is your answer
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