Question

At what temperature would the root mean square speed of oxygen molecules be 13,0m/s

Answer 1

Mean square speed of the Oxygen = 130 m/s.

Using the formula,

Mean Square Speed = $\sqrt{\frac{2RT}{M} }$

Where R is the Universal constant of gas, and T is the temperature, M is the Molar mass of the Oxygen = 32 × 10⁻³ g.

∴ 130 = √[2 × 8.31T/(32 × 10⁻³)]

130 × √(32 × 10⁻³) = √(8.31 × 2T)

∴ √T = 5.7

∴ T = 32.49 K.

Hope it helps.

Answer 2

Answer:

Mean square speed of the Oxygen = 130 m/s.

Using the formula,

Mean Square Speed

Where R is the Universal constant of gas, and T is the temperature, M is the Molar mass of the Oxygen = 32 × 10⁻³ g.

∴ 130 = √[2 × 8.31T/(32 × 10⁻³)]

130 × √(32 × 10⁻³) = √(8.31 × 2T)

∴ √T = 5.7

∴ T = 32.49 K.

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