At what tempreture, would the resistance of a copper wire be double its resistance at 0°C? If Alpha = 1/273°C^-1.
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Answer:
Given:
R=2R
o
α=3.9×10
−3
C
−1
ΔT=T−T
o
R
o
and T
o
are resistance and temperature at 0
∘
C
R and T are resistance and temperature at T
∘
C
R=R
o
(1+αΔT)
Substituting the given information,
2R
o
=R
o
(1+αΔT)
2=1+αΔT
1=αΔT
1=3.9×10
−3
ΔT
ΔT=256.41
∘
C
T−T
o
=T−0=T=256.41
∘
C
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