Question

At what time Rs.900 will become Rs. 1008 on simple interest of 6% per annum ?

Answer 1

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Your Answer...

Given:
P = 900 Rs. , R = 6% per annum , Amount = 1008 Rs.

Interest in Time T year = Amount - P

I = 1008 - 900

I = 108 Rs.

Now,

We know That,

Simple Interest, I = P×T×R/100

=> T = I×100/(P×R)

=> T = 108×100/(900×6)

=> T = 108/(9×6)

=> T = 2

Hence ,

In 2 years 900Rs. will become Rs. 1008 at given rate 6% per annum.

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Answer 2

P=Rs.900
A=Rs.1008
R=6%
therefore S.I=A-P
Rs.1008-Rs900=108
$t = \frac{s.i \times 100}{p \times r}$
$t = \frac{108 \times 100}{900 \times 6}$

t=2 years