Math, asked by jied6464, 1 year ago

At what time will B catch up with A, if A starts from a place at 11.00 A.M. and travels at a speed of 3.5 kmph, B starts at 1.00 P.M. and travels with speeds of 1 kmph for 1 hour, 2 kmph for the next 1 hour, 3 kmph for the next 1 hour and so on.
A) 8 : 47 pm
B) 6 : 40 pm
C) 8 : 42 pm
D) 7 : 40 pm

Answers

Answered by Anonymous
1
At what time will B catch up with A, if A starts from a place at 11.00 A.M. and travels at a speed of 3.5 kmph, B starts at 1.00 P.M. and travels with speeds of 1 kmph for 1 hour, 2 kmph for the next 1 hour, 3 kmph for the next 1 hour and so on.
A) 8 : 47 pm
B) 6 : 40 pm✅✅✅
C) 8 : 42 pm
D) 7 : 40 pm
Answered by AJThe123456
2
Heyy mate ❤✌✌❤

Here's your Answer....

At 1 pm ... Distance between A and B = 2x3.5 = 7 kms
at 2 pm .....Distance between A and B = 7 + 3.5 - 1 = 9.5 kms
At 3 pm ....Distance between A and B = 9.5 + 3.5 - 2 = 11 kms.
..
..
..
At 7 pm distance between A and B = 3 kms.
From 7 pm to 8 pm, speed of A = 3.5 kmph
speed of B = 8 kmph
Relative speed = 4.5 kmph

Time taken by B to meet A = 3/4.5 hrs = 30/45 hrs = 120/3 mins = 40 mins.

So meeting time is 7 : 40 PM.
✔✔✔
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