at what time will sum of Money doubles itself at 10% per annum (answer it with
solution of 7th std)
Answers
Answered by
0
Answer:
let principal be p
2p= p*r*t/100
2p=p*10*t/100
t=100*2p/p*10=20 years
Answered by
1
Answer:
10 years
Step-by-step explanation:
We are assuming that this is a case of simple interest
P = initial amount
R = rate of interest per cent per year = 10
T = time period in years
A = final amount at the end of period T
SI = Simple Interest = (P*R*T)/100
A = P + SI
We are given that money doubles.
This means that:
Final Amount = 2*(Initial Amount)
=> A = 2P
=> P + SI = 2P
=> P = SI
=> P = P*R*T/100
=> 100 = R*T
Given R = 10
=> 100 = 10*T
=> T = 10
Answer: Money will double in 10 years at 10% p.a. simple interest
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