At what velocity the kinetic energy of a body is equal to its rest mass energy.
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The answer is 0.87c
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consider the Einstein relativistic equation
E = Ek + Er
(Er is the rest mass energy)
So,
mc² = Ek + m₀c²
Therefore kinetic energy of a particle is:
Ek = mc² - m₀c²
now applying the condition:
Ek = Er, and also relativistic mass m=m₀/√(1 - v²/c²)
m₀c²/√(1 - v²/c²) - m₀c² = m₀c²
m₀c²/√(1 - v²/c²) = 2m₀c²
1/√(1 - v²/c²) = 2
√(1 - v²/c²) = 1/2
1 - v²/c² = 1/4
v²/c² = 3/4
v = c√0.75
v = 259807.621 km/s
v=0.87c
hope it helps
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