at what weight above the Earth's surface would the value of acceleration due to gravity be half of what it is on the surface take radius of a Earth to be R
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0
Answer:
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2
g
=
(R+h)
2
Gm
g=
R
2
Gm
2
1
=
(R+h)
2
R
2
R+h=
2
R
R=0.41R
=0.41×6.4×10
6
m=2.6×10
6
m
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