Question

At which angle the stone is projected for maximum horizontal range?​

Answer 1

Answer:

The horizontal component of the velocity does not change. If the angle of projection is 75.96 degrees the maximum height is equal to the horizontal range.

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Answer 2

Answer:

R=u²sin2Θ/g

R is maximum when sin2Θ = 1,

ie R=u²/2g

Sin2Θ=1

2Θ = 90°

Θ = 90/2 =45°

So range is maximum when Θ is 45°

The stone should be projected at 45°