Question

at which condition under which Kp >Kc a)∆n=0 b)∆n>o c)∆n<0 d)∆n≥0

Answer 1

Explanation:

$K_p = K_c {(RT)}^{\Delta n} \\ \\ So \: \: for \: \: K_p > K_c \: \: \boxed{\Delta n > 0}$

Therefore option (b) is correct

Answer 2

Answer:

here is your answer

Explanation:

Kp=Kc(RT)Δn

If Δn=0,Kp=Kc

If Δn>0,thenKp>Kc

If Δn<0,thenKp<Kc

For the reaction: H2(g)+Cl2(g)⇌2HCl(g)

Δn is the number of moles of gaseous products - number of moles of gaseous reactants in a balanced equation.

Δn=2−(1+1)=0

∴Kp=Kc

i hope it is helpful