At which height from the earth's surface does the acceleration due to gravity decrease by 75% of its value
at earth's surface ?
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Answer:
Acceleration due to gravity at height h from earth surface is:
g
′
=g(1−
R
2h
)
g
g
′
=(1−
R
2h
)
100
75
=(1−
R
2h
)
100
25
=
R
2h
h=
8
R
=
8
6.4×10
6
=8×10
5
m=800km
Thus, at 800km above earth surface g becomes 75% of its value on earth surface
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