At which height from the earth's surface does the acceleration due to gravity decrease by 1% ?
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Explanation:
The new value of gravity at a height h is given as g′= gR² / (R+h)²
As visible from the formula that incresing h results in decresing gravity.So just put g′=0.99g i.e. 1% less than g where g is gravity at surface.
so we get 0.99g = gR² / (R+h)²
Solving the equation we get h=0.005R
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