Question

at which height from the earth surface does the acceleration due to gravity decrease by 75% of it's value at earth​

Answer 1

Given :-

Radius of earth = 6400 Km

g = 10 m/s²

g' = (100-75g)%= 25/100g

g' = g(1+h/R)²

25/100g = g(R+h/R)²

√25/100 = R+h/R

5/10 = 6400+h/6400

32000 = 64000 + 10h

32000 = 10h

h = 3200 m