Question

At which point ,the graph of linear equation 2x+3y=6 cuts the y-axis?

Answer 1

2 x + 3 y =6
point on x axis will be (0, y )
thus
0 x + 3y = 6
y = 6/3
y = 2
hence the point will be (0,2 )

Answer 2

The point at which the graph of linear equation 2x + 3y = 6 cuts the y-axis is (0, 2).

Step-by-step explanation:

We have to find the point at which the graph of linear equation 2x + 3y=6 cuts the y-axis.

Firstly, as we know that the point on the y-axis will have the x-coordinate as 0, this means that the point at which the graph of linear equation 2x + 3y = 6 cuts the y-axis is '(0, y)'.

Now, substituting this coordinate into the given linear equation, we get;

$2x+3y=6$

$(2\times 0)+3(y)=6$

$0+3y=6$

$3y=6$

$y =\frac{6}{3}$

y = 2

Hence, the point at which the graph of linear equation 2x + 3y = 6 cuts the y-axis is y(0, 2).