Question

At which point, the potential energy and kinetic energy will be the same in a free-falling body?​

Answer 1

Answer:

At A,velocity =0=u

KE=

2

1

mv

2

=0

PE=mgh,TE=PE+KE=mgh

At B,velocity v:

v

2

=u

2

+2as

v

2

=2gx

KE=

2

1

mv

2

=mgx

PE=mg(h−x)

Total energy TE=PE+KE

=mg(h−x)+mgx=mgh

At C,velocity v:

v

2

=u

2

+2as

v

2

=2gh

KE=

2

1

mv

2

=mgh

PE=0

TE=PE+KE=mgh

Answer 2

Answer:

at the midpoint of the path of free -falling body the potential energy and kinetic energy will be same in a free falling body

please mark brainlist