At which temperature 0.006 % w/V urea solution has osmotic pressure 0.0246 atmosphere?
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Answer: as given in question 0.006%W/V
→ break the statement
0.006 g in 1000 ml
π = 0.0246 atm
T = ?
Explanation:
π = WRT / MV
T = WR / MπV
T = 0.246 • 60 • 0.1 ÷ 0.006 •0.0821
= 1.476 ÷ 0.0004926
T =2996.3 K
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