At which value in the domain does mc027-1.jpg? mc027-2.jpg mc027-3.jpg mc027-4.jpg mc027-5.jpg mc027-6.jpg
Answers
Answer:
1,2,3,4,5,6 is in domain. mc027 is fix.
Step-by-step explanation:
solve equation
mc27-1jpg
Final result :
mc27 - jpg
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "c0" was replaced by "c^0".
(2): Dot was discarded near "1.j".
Step by step solution :
Step 1 :
Trying to factor as a Difference of Cubes:
1.1 Factoring: mc27-jpg
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0+b3 =
a3+b3
Check : m 1 is not a cube !!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Final result :
mc27 - jpg