Question

At zero centigrade ice and water in equilibrium then change enthalpy 6kj and its change in entropy

Answer 1

Explanation:

The molar latent heat of fusion, which is an alternative name given to the enthalpy of fusion, tells you how much heat is required in order to convert a specific amount of a given substance, either a gram or a mole, from solid at its melting point to liquid at its melting point.

Ice is said to have a molar enthalpy of fusion equal to

Δ

H

fus

=

6.0 kJ mol

−

1

This means that in order to melt  

1

mole of ice at its normal melting point of  

0

∘

C

, you must supply it with  

6.0 kJ

of heat.

Now, your sample of ice has a mass of  

36 g

, so the first thing to do here is to convert it to moles by using the molar mass of water

36

g

⋅

1 mole H

2

O

18.015

g

=

1.998 moles H

2

O

You can now use the molar enthalpy of fusion as a conversion factor to help you figure out how much heat must be supplied to your sample

1.998

moles ice

⋅

6.0 kJ

1

mole ice

=

12 kJ

−−−−−