at zero degree centigrade and 760 mm of Mercury pressure a gas occupies a volume of 100 cm cube the Kelvin temperature is increased by 1 v x while the temperature is decreased by 1 v calculate the final volume
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Given
T1 = 0°C=273k. T2=1/5*(273)+273=327.6k
P1= 760mm. P2=760+1/2*(760)=1140mm
V1= 100cc. V2=?
using ideal gas eqn.
P1*V1/T1=P2*V2/T2
760*100/273=1140*VE/327.6
On solving V2 will be equal to 80cc
hope it helps
mark the BRAINLIEST plzz
jacobcunningham202:
great answer
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here is your answer
#bebrainly
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