@akshaya890 can you help in my question
construct a square-root spiral
Answers
Answer:
1. Mark a center point O.
2. From point O, draw a horizontal line OA of length 1 cm.
3. From point A, draw a perpendicular line AB of length 1 cm.
4. Join OB, here OB = √2.
5. Now, from point B, draw a line perpendicular to OB (Use set squares) of length 1 cm.
6. Join OC, here OC = √3.
7. Repeat steps 4,5,6 for √4 √4 √4
8. Our square root spiral is ready.
Step-by-step explanation:
HOPE IT HELPS!!
||^_^||
Answer:
TIONS
WORKSHEETS
UNSEEN PASSAGES
CBSE NOTES
ENGLISH GRAMMAR
NCERT BOOKS
10TH SAMPLE PAPERS 2021
Skip to main content
Skip to primary sidebar
Skip to footer
MENU
CBSE Tuts
CBSE Maths notes, CBSE physics notes, CBSE chemistry notes
NCERT Class 9 Maths Lab Manual – Construct a Square Root Spiral
NCERT Class 9 Maths Lab Manual – Construct a Square Root Spiral
OBJECTIVE
To construct a square root spiral.
Materials Required
Adhesive
Geometry box
Marker
A piece of plywood
Prerequisite Knowledge
Concept of number line.
Concept of irrational numbers.
Pythagoras theorem.
Theory
A number line is a imaginary line whose each point represents a real number.
The numbers which cannot be expressed in the form p/q where q ≠ 0 and both p and q are integers, are called irrational numbers, e.g. √3, π, etc.
According to Pythagoras theorem, in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of other two sides containing right angle. ΔABC is a right angled triangle having right angle at B. (see Fig. 1.1) NCERT Class 9 Maths Lab Manual - Construct a Square Root Spiral 1
Therefore, AC² = AB² +BC²
where, AC = hypotenuse, AB = perpendicular and BC = base
Procedure
Take a piece of plywood having the dimensions 30 cm x 30 cm.
Draw a line segment PQ of length 1 unit by taking 2 cm as 1 unit, (see Fig. 1.2)
NCERT Class 9 Maths Lab Manual - Construct a Square Root Spiral 2
Construct a line QX perpendicular to the line segment PQ, by using compasses or a set square, (see Fig. 1.3)NCERT Class 9 Maths Lab Manual - Construct a Square Root Spiral 3
From Q, draw an arc of 1 unit, which cut QX at C(say). (see Fig. 1.4)
NCERT Class 9 Maths Lab Manual - Construct a Square Root Spiral 4
Join PC.
Taking PC as base, draw a perpendicular CY to PC, by using compasses or a set square.
From C, draw an arc of 1 unit, which cut CY at D (say).
Join PD. (see Fig. 1.5)
NCERT Class 9 Maths Lab Manual - Construct a Square Root Spiral 5
Taking PD as base, draw a perpendicular DZ to PD, by using compasses or a set square.
From D, draw an arc of 1 unit, which cut DZ at E (say).
Join PE. (see Fig. 1.5)
Keep repeating the above process for sufficient number of times. Then, the figure so obtained is called a ‘square root spiral’.
Demonstration
In the Fig. 1.5, ΔPQC is a right angled triangle.
So, from Pythagoras theorem,
we have PC² = PQ² + QC²
[∴ (Hypotenuse)² = (Perpendicular)² + (Base)²]
= 1² +1² =2
=> PC = √2
Again, ΔPCD is also a right angled triangle.
So, from Pythagoras theorem,
PD² =PC² +CD²
= (√2)² +(1)² =2+1 = 3
=> PD = √3
Similarly, we will have
PE= √4
=> PF=√5
=> PG = √6 and so on.
Spamming is nothing sister it is giving irrelevant answers or telling I don't know and claiming points.Many do it .I answer honestly