Math, asked by wahab761, 10 months ago

Atank is filled by three pipes with uniform flow.The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by third pipe alone.The second pipe fills the tank 5hours faster than the first pipe and 4hours slower than the third pipe .The time required by the first pipe is:

Answers

Answered by Anonymous
15

Time taken by pipe 1 alone is = 15 hours.

Attachments:
Answered by StarGazer001
22

Time taken by pipe 1 = 15 hours

Attachments:
Similar questions