Question

, atanx= btany
a sinx+bcosx = c
bsiny+ acosy =d
then a²/bsquare=



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Answer 1

Answer:

Correct option is

C

No solution

Since, ∣asinx=bcosx∣≤a2+b2,∀x∈R

⇒∣c∣≤a2+b2

But ∣c∣>a2+b2

∴asinx=bcosx=c

It does not hold for any x∈R

So, it has no solution.