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Find the zeroes of the polynomial (3x)2+4x+1 and verify the relation between zeroes and the cofficient​

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Answer:

$\huge given$

$</p><p>Find the zeroes of the polynomial (3x)2+4x+1 and verify the relation between zeroes and the cofficient$

$\huge \mathfrak solution \star$

$\huge \bold \4x2 – 3x – 1 Splitting the middle term, we get, 4x2-4x+1x-1 Taking the common factors out, we get, 4x(x-1) +1(x-1) On grouping, we get, (4x+1)(x-1) So, the zeroes are, 4x+1= 0⇒ 4x=-1 ⇒x= (-1/4) (x-1) = 0 ⇒ x=1 Therefore, zeroes are (-1/4) and 1 Verification: Sum of the zeroes = – (coefficient of x) ÷ coefficient of x2 α + β = – b/a 1 – 1/4 = – (- 3)/4 = ¾ Product of the zeroes = constant term ÷ coefficient of x2 α β = c/a 1(- 1/4) = – ¼ – 1/4 = – 1/4Read more on Sarthaks.com - https://www.sarthaks.com/878292/find-the-zeroes-polynomial-and-verify-relation-between-coefficients-zeroes-polynomial$