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If first and last term are 5 and 45
Respectively. If
terms
and
Sum
of its terms is 400.
the
find d?
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1
Given, a=5
l=45
Sn=400
Sn=n/2 (first term+last term )
400=n/2 (5+45)
800=n(50)
800/50=n
16=n
Now...
a16= a+(n-1)d
45=5+(16-1)d
45-5=15d
40/15=d
2.67=d
HOPE IT HELPS...
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