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s y tacy ² - 1 1 0 ²y + 10 xy², 10x²y - 11 xy²
Xc²y + scy2 + (11) Jc²y + 10x42 + (-10) xy + l-
c2y + (-1) x ²4 + 610) oc²y + xy² + 10x4² 4 6-11
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Answer:
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Secondary School Math 5 points
148/x+231/y=527/xy ; 231/x+148/y=610/xy Solve the simultaneous equation
Ask for details Follow Report by StarTbia 26.06.2018
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Robin0071
Robin0071 Ace
Solution:-
given by:-
\frac{148}{x} + \frac{231}{y} = \frac{527}{xy} \\ 231x + 148y = 527...............(1) \\ \frac{231}{x} + \frac{148}{y} = \frac{610}{xy} \\ 148x + 231y = 610................(2) \\ multipy \: eq(1)with148 \: and \: eq(2) \: with \: 231. \\ 31488x + 21904y = 77996............(3) \\ 31488x + 53361y = 140910..........(4) \\ substrac \: eq(3) \: from \: eq(4) \\ we \: have \\ 31488x + 53361y = 140910 \\ 31488x + 21904y = 77996 \\
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31457y = 62914 \\ y = 2 \\ put \: y = 2 \: in \: eq(1) \\ 231x - 148 \times 2 = 527 \\ 231x = 527 - 296 \\ x = \frac{231}{231} \\ x = 1
here , ( x , y ) = ( 1, 2)
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Comments (2) Report
rohitkumargupta
check Equation once again
Robin0071
ya typing mis. 31488 place of writen34188
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rohitkumargupta
rohitkumargupta Genius
148/x + 231/y = 527/xy
(148y + 231x)/xy = 527/xy
148y + 231x = 527-----------( 1 )
231/x + 148/y = 610/xy
(231y + 148x)/xy = 610/xy
231y + 148x = 610------------( 2 )
adding---------( 1 ) & -----------( 2 )
231x + 148y = 527
148x + 231y = 610
---------------------------
379x + 379y = 1137
x + y = 3-----------( 3 )
subtracting-------( 1 ) &-----( 2 )
231x + 148y = 527
148x + 231y = 610
--------------------------
83x - 83y = -83
x - y = -1------------( 4 )
From-------( 3 )&-------( 4 )
x + y = 3
x - y = -1
------------
2x = 2
x = 1 [ put in -----( 3 )]
1 + y = 3
y = 2