Atent is in
is in the shape of a cylinder surmounted by a conical
eter of the cylindrical part
mounted by a conical top. If the height and
28m, find the area of the canya
| m and 4 m respectively, and the slant height of the
the canvas used for making the tent. Also, find the
anvas of the tent at the rate of 35
the
Cam
a
Tate of 500 per m2. (Note that the base of the tent will not
overed with canvas.)
nop is 2.8m
plzz help me
Answers
Answer:
so what is the diameter of the cylinder ?
it's not specified in the question
and is 4 m the slant height or the height or radius ?
sorry but I'm not able to understand the question.
anyways , I found a similar question ( it looks like its the same one) and according to it ,
h ( cylinder )= 2.1 m
d ( cyl) = 4 m
r = d/2 = 4/2 = 2m
slant height ( l ) [ cone ] = 2.8 m
Area of the canvas used
= CSA of Cone + CSA of Cylinder
= πrl + 2πrh
= 22/7 × 2× 2.8 + 2× 22/7 ×2 ×2.1
={22 × 2 × 0.4 } + { 2 × 22 × 2 × 0.3}
= 44 × 0.4 + 88 × 0.3
= 17.6 + 26.4
= 44.0 m^2 / sq. units
area = 44m^2
cost of canvas for one meter square
= ₹500
cost of canvas for 44 meter square
= 500×44
= ₹22,000
hope this will be helpful
height of cylinder = 2.1 m
diameter of cylinder = 4 m
r = d/2 = 4/2 = 2m
slant height ( l ) of cone = 2.8 m
Area of the canvas used
= CSA of Cone + CSA of Cylinder
= πrl + 2πrh
= 22/7 × 2× 2.8 + 2× 22/7 ×2 ×2.1
={22 × 2 × 0.4 } + { 2 × 22 × 2 × 0.3}
= 44 × 0.4 + 88 × 0.3
= 17.6 + 26.4
= 44.0 m^2 / sq. units
area = 44m²
cost of canvas for one meter square
= ₹500
cost of canvas for 44 meter square
= 500×44
= ₹22,000
hope this will be helpful