Question

Ater travelling 50km, a train is meeting with an accident and travels at (3/4)th of the usual Speed and reaches 45min late. Had a accident happened 10km further on it would have reached 35min late. Find the udual speed​

Answer 1

Answer:

2/4 speed

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Answer 2

• Train proceeds at 3/4 S where S is his usual speed means 1/4 decrease in the speed which will lead to 1/3 increase in the time.[ As S *T = D, Speed is inversely proportional to time when distance is constant].Now, the main difference come in those 24 km and the change in difference of time = 35 - 25 = 10 m= 1 / 3 *T = 10 where T is the time required to cover the distance of (50 - 74) = 24 kmT = 30 min = 0.5 hoursSpeed of the train = 24 / (0.5) = 48 kmph

So the answer is 48 kmph