Question

@find the equation of the lines of
intersection of the plane 3x+4y +2 = 0
and the core 15x²_324²-72² = 0​

Answer 1

Answer:

intersection of the given planes is

(3x−4y+5z−10)+k(2x+2y−3z−4)=0

⇒ 3x−4y+5z−10+2kx+2ky−3kz−4k=0

⇒ (3+2k)x+(−4+2k)y+(5−3k)z−10−4k=0 ----- ( 1 )

The given line is

x=2y=3z

Dividing this equation by 6, we get

⇒

6

x

=

3

y

=

2

z

The direction ratios of this line are proportional to 6,3,2.

So, the normal to the plane is perpendicular to the line whose direction are proport

Step-by-step explanation:

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