ath term=2n+13 then that are sum of n terms
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Answered by
1
Answer:
a1=2+13=15
a2=2×2+13=4+13=17
Now,d=17-15=2
Sn=n/2[2×15+(n-1)2]
=n/2[30+(n-1)2]
=n[15+n-1]
=n[n+14]
=n^2+14n
Answered by
0
Answer:
I think the answer is : n ( 4n + 26 + dn - d)
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Step-by-step explanation:
You use the formula : Sn = n ( a + (n - 1)d)
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