Hindi, asked by aminaparveen267, 7 months ago

अथवा "नारी शिक्षा”।
1.निम्नलिखित वादों के पुल्लिंग और स्त्रीलिंग पिवी
वृक्ष; राह; लिथि, चाँदी; दूय्य ।
(5)​

Answers

Answered by routsandipbarun
0

Answer:

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Answered by DeepakAyoutuber
0

Explanation:

Original Number = 41

Step-by-step explanation:

Given:

One of the two digit number is 4 times the other digit.

After interchanging digits and adding resulting number with original we get 55.

To Find:

What is the original number ?

Solution: Let the tens and ones digit of original number be x and y respectively. Therefore original number is 10x + y

One digit = 4 times of other

x = 4y........(1)

[ Now interchanging the digits of number new number formed will be ]

Reversed number = 10y + x

A/q

After interchanging digits and adding resulting number with original we get 55.

\implies{\rm }⟹ 10y + x + 10x + y = 55

\implies{\rm }⟹ 11y + 11x = 55

\implies{\rm }⟹ 11(y + x) = 55

\implies{\rm }⟹ y + x = 55/11

\implies{\rm }⟹ y + 4y = 5

\implies{\rm }⟹ 5y = 5

\implies{\rm }⟹ y = 5/5

\implies{\rm }⟹ y = 1

So the digits of number are

• Ones digit is y = 1

• Tens digit is x = 4y = 4 × 1 = 4

Hence the original number is 10x + y

= 10(4) + 1

= 41

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