Question

athe angle ofbelevations of an anti aircraft gun is 70 degree an the muzzle velocity is 900m/s .farward time what time should fuse be best it the shell is two exploned at the attitude of 1500m\s .g=9.8​

Answer 1

Explanation:

At any time t, a projectile's horizontal and vertical displacement are:

x = Vo t Cos θ where Vo is the initial velocity, θ is the launch angle

y = Vo t Sinθ – ½gt^2

In this case, we have Vo = 900m/s, θ = 70° and y = 1500m

So, 1500 = 900(t)(Sin70) – 4.905t^2

4.905t^2 – 845.7t + 1500 = 0

t = 1.792s (on the way up) or 170.63s (on the way back down)

Set the fuse for 1.792 seconds