Question

Athe area of a rhombus is 48 cm square one of its diagonals measures 8cm what is the length of the other diagonal

Answer 1

Answer:

12 cm

Step-by-step explanation:

A=PQ/2

then

48= (Px8)/2

P= (48x2)/8

P= 12 cm

Answer 2

Given,

The area of a rhombus is = 48 cm square.

One of its diagonal is = 8 cm.

To find out,

The length of other diagonal.

Solution:

Let the length of other diagonal be "x".

$Area \: of \: rhombus \: = \frac{1}{2} \times d1 \times d2$

Here, d1 = diagonal 1 = 8cm

d2 = diagonal 2 = x cm

$Area \: of \: rhombus \: = \frac{1}{2} \times 8 \times x \\ \\ \: 48 = 4x \\ \\ x = \frac{48}{4} \\ \\ x = 12 \: cm$

Therefore the length of the other diagonal of rhombus is 12 cm.