Math, asked by vaishnavipamarthi4, 6 months ago

ATHEMATICS - C3 - PART 1
MENSURATION
In the following figure ABC is an equilateral triangle and C is the centre of the circle, A and B lie on
the circle. If the diameter of the circle is 28 cm, then the area of the shaded region is [ ]
A
B.
a) 102-40/3)]ow? b) (103 -98345)cm ?
(109 – 38/3)cm
С
d) Data incompleted
The number of revolutions per minute must the​

Answers

Answered by aaravs618gmailcom
2

Answer:

Area of shaded region = Area of Square ABCD− Area of 4 quadrants of circle

Side of square =14cm

Area of Square =(side)

2

=(14)

2

=256cm

2

Radius of circle =

2

14

=7cm

Area of quadrant of circle =

4

1

πr

2

Area of 4 quadrants of circle =4(

4

1

πr

2

)=

7

22

×7×7=154cm

2

Area of shaded region =256−154=102cm

2

Answered by rashmimarkam90
0

Answer:

= 26 cm, b = 28 cm and c = 30 cm ... Let the radii of two circles be r1 and r2 respectively.

Attachments:
Similar questions