Physics, asked by rohitroman13, 1 year ago

athlete completes one round of a circular track of diameter 14 m in 20 seconds what will be distance covered and the displacement at the end of 2 minute and 10 seconds​

Answers

Answered by razzkumar96
5

Answer:

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Answered by dna63
2

\mathit{\large{\red{\underline{\underline{Answer:-}}}}}

\textbf{\large{\pink{\underline{Step by step Explanation:-}}}}

\mathcal{\underline{Given,,}}

\mathtt{diameter(d)=14m}

\mathcal{\underline{Hence,,}}

\mathtt{redius(r)=\frac{d}{2}}

\mathtt{\implies{\frac{14}{2}}}

\mathtt{\implies{7m}}

\mathcal{\underline{And,,}}

\mathtt{perimeter=2\pi{r}}

\mathtt{\implies{2\times{\frac{22}{7}}\times{7}}}

\mathtt{\implies{44m}}

\mathcal{\underline{Hence,,}}

\textit{athlete completes one round(44m) of the circular track in 20 seconds}

\mathtt{speed=\frac{distance}{time}}

\mathtt{\implies{\frac{44m}{20}}}

\mathtt{\implies{2.2m/sec}}

\textit{athlete runs 2.2m in a sec}

\textit{then,,in 2 minutes 10 seconds(130 seconds) the distance covered by athlete= }

\mathtt{\implies{speed\times{time}}}

\mathtt{\implies{2.2m\times{130}}}

\mathtt{\implies{286m}}

\textbf{\large{\blue{please mark it as Brainliest answer.. thanks..}}}


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