Question

Athree hinged parabolic arch of span 40m and rise 8m carries a concentrationload of 120 KN at a horizontal distanceof 10 m from the left end. Find the relationsat the supports?

Good Afternoon Legends
:D​

Answer 1

Answer:

Good Afternoon

Step-by-step explanation:

Athree hinged parabolic arch of span 40m and rise 8m carries a concentrationload of 120 KN at a horizontal distanceof 10 m from the left end. Find the relationsat the supports

Answer 2

Answer:

Support rxn :

∑MA=0(↻+ve)

200×8+150×16+(50×20)×30−VB×40=0

VB=850KN

∑FY=0(↑+ve)

VA−200−150−(50×20)+850=0

VA=500KN

To find horizontal thrust:

Taking BMc = 0

consider part (CA)

500×20−150×4−200×12−H×8=0

H=875KN

Step-by-step explanation:

Good Afternoon :)